Re: ordering of join using ON expression = any (array)

Sorry, I'm using 8.1, not 8.4.

On Tue, May 17, 2011 at 10:06 AM, Gerhard Hintermayer <
gerhard(dot)hintermayer(at)gmail(dot)com> wrote:

> Hi,
> is there a way to sort the joined tuples in the way they are in a the
> joined array ? BTW I'm using 8.4 (_I_ know I should upgrade, but management
> thinks we shouldn't :-( )
> I'd like to join 2 tables based on a column, where the column is an array
> in one table, but I still need to keep the order of tuples as they were
> originally in the array.
>
> What I now get is e.g. if the array contains A,B,C , I get rows B, C and A,
> but I'd like to get one row containing A, the B, then C
>
> My query is:
> select * from produkt inner join (select a_nr,komp as p_code from r_mi_sfm
> where a_nr=20110) as auftrag on (produkt.p_code = any(auftrag.p_code));
>
> and explain says:
> Nested Loop (cost=201.83..2656.51 rows=26992 width=98)
> Join Filter: ("inner".p_code = ANY ("outer".komp))
> -> Index Scan using idx_r_mi_sfm_a_nr on r_mi_sfm (cost=0.00..25.39
> rows=7 width=58)
> Index Cond: (a_nr = 20110)
> -> Materialize (cost=201.83..278.95 rows=7712 width=40)
> -> Seq Scan on produkt (cost=0.00..194.12 rows=7712 width=40)
>
> thanks for any input
> Gerhard
>