Re: Plan for in with one argument

From: Alban Hertroys <dalroi(at)solfertje(dot)student(dot)utwente(dot)nl>
To: Marcus Engene <mengpg2(at)engene(dot)se>
Cc: pgsql-general(at)postgresql(dot)org
Subject: Re: Plan for in with one argument
Date: 2010-07-11 10:42:12
Message-ID: B30C854F-70F7-424C-861E-3FE73BCD5CC1@solfertje.student.utwente.nl
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On 11 Jul 2010, at 11:38, Marcus Engene wrote:

> Hi List,
>
> With automated queries where I have COLUMN IN (), I get a different plan from COLUMN = (). That would make sense if there are several arguments, but in the case with just one argument the penalty can be seveare. One query went from 5s execution time to a few houndreds of mS when I changed IN to = if the number of arguments is 1.
>
> Is there a technical reason for not treating IN with one argument as = in that case?

It does that already for constant IN-lists:
=> create table test (id serial PRIMARY KEY);
=> insert into test (id) SELECT nextval('test_id_seq') from generate_
series(1, 10000);
=> ANALYZE test;
=> explain analyse select * from test where id IN (15);
QUERY PLAN
--------------------------------------------------------------------------------
Index Scan using test_pkey on test (cost=0.00..8.27 rows=1 width=4) (actual time=0.024..0.029 rows=1 loops=1)
Index Cond: (id = 15)
Total runtime: 0.102 ms
(3 rows)

However, you're using a subquery to get the IN-list. I'm pretty sure the planner cannot know for certain that your subquery will return only one row, so it cannot substitute your IN(subquery) with =(subquery).

You'd probably be better off using an EXISTS instead of an IN there, that should certainly help for cases where the subquery returns many records, but it also gives the planner a better idea of your intentions.

> pondDump=> explain analyze select
> pic.objectid as pic_objectid
> from
> pond_item_common pic
> where
> pic.pond_user IN (select pu2.objectid from pond_user pu2 where username_locase IN ('iceberger'))
> limit 100;
> QUERY PLAN
> ----------------------------------------------------------------------------------------------------------------------------------------------
> Limit (cost=15.41..396.89 rows=100 width=4) (actual time=0.047..0.061 rows=11 loops=1)
> -> Nested Loop (cost=15.41..1400.19 rows=363 width=4) (actual time=0.046..0.056 rows=11 loops=1)
> -> HashAggregate (cost=8.28..8.29 rows=1 width=4) (actual time=0.026..0.026 rows=1 loops=1)
> -> Index Scan using pond_user_c2 on pond_user pu2 (cost=0.00..8.27 rows=1 width=4) (actual time=0.017..0.018 rows=1 loops=1)
> Index Cond: ((username_locase)::text = 'iceberger'::text)
> -> Bitmap Heap Scan on pond_item_common pic (cost=7.13..1387.36 rows=363 width=8) (actual time=0.015..0.024 rows=11 loops=1)
> Recheck Cond: (pic.pond_user = pu2.objectid)
> -> Bitmap Index Scan on pond_item_common_x1 (cost=0.00..7.04 rows=363 width=0) (actual time=0.012..0.012 rows=11 loops=1)
> Index Cond: (pic.pond_user = pu2.objectid)
> Total runtime: 0.181 ms
> (10 rows)
>
> pondDump=> explain analyze
> select
> pic.objectid as pic_objectid
> from
> pond_item_common pic
> where
> pic.pond_user = (select pu2.objectid from pond_user pu2 where username_locase IN ('iceberger'))
> limit 100;
> QUERY PLAN
> -------------------------------------------------------------------------------------------------------------------------------------
> Limit (cost=15.41..395.88 rows=100 width=4) (actual time=0.043..0.055 rows=11 loops=1)
> InitPlan 1 (returns $0)
> -> Index Scan using pond_user_c2 on pond_user pu2 (cost=0.00..8.27 rows=1 width=4) (actual time=0.017..0.018 rows=1 loops=1)
> Index Cond: ((username_locase)::text = 'iceberger'::text)
> -> Bitmap Heap Scan on pond_item_common pic (cost=7.13..1388.27 rows=363 width=4) (actual time=0.042..0.053 rows=11 loops=1)
> Recheck Cond: (pond_user = $0)
> -> Bitmap Index Scan on pond_item_common_x1 (cost=0.00..7.04 rows=363 width=0) (actual time=0.038..0.038 rows=11 loops=1)
> Index Cond: (pond_user = $0)
> Total runtime: 0.096 ms
> (9 rows)
>
> pondDump=>
>
> Best regards,
> Marcus
>
>
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>
>

Alban Hertroys

--
If you can't see the forest for the trees,
cut the trees and you'll see there is no forest.

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