From: | Guyren Howe <guyren(at)gmail(dot)com> |
---|---|
To: | pgsql-general <pgsql-general(at)postgresql(dot)org> |
Subject: | SELECT DISTINCT ON removes results |
Date: | 2016-10-28 20:39:19 |
Message-ID: | AF05A411-E3A8-4317-8D6B-D4D658991C8B@gmail.com |
Views: | Raw Message | Whole Thread | Download mbox | Resend email |
Thread: | |
Lists: | pgsql-general |
Using 9.5, this query:
SELECT o.id,
a.number AS awb
FROM pt.orders o
LEFT JOIN (
SELECT DISTINCT ON ((string_agg(air_way_bills.number::text, ','::text)))
string_agg(air_way_bills.number::text, ','::text) AS number,
air_way_bills.order_id
FROM pt.air_way_bills
GROUP BY air_way_bills.order_id) a ON a.order_id = o.id
gives me null for awb. Removing the DISTINCT ON clause:
SELECT o.id,
a.number AS awb
FROM pt.orders o
LEFT JOIN (
SELECT string_agg(air_way_bills.number::text, ','::text) AS number,
air_way_bills.order_id
FROM pt.air_way_bills
GROUP BY air_way_bills.order_id) a ON a.order_id = o.id
where o.id = 2792;
gives me an awb. I'm confused about how this can be.
From | Date | Subject | |
---|---|---|---|
Next Message | David G. Johnston | 2016-10-28 20:50:52 | Re: SELECT DISTINCT ON removes results |
Previous Message | David G. Johnston | 2016-10-28 20:07:22 | Re: How to hint 2 coulms IS NOT DISTINCT FROM each other |