Re: Given N, finding the interval of N hours with max(sum(..))

I have found an initial solution. For an interval N of 3 hours the query can
be:

select distinct poi,first_value(start_date) OVER w as
start_date,first_value(end_date) OVER w as end_date,first_value(the_sum)
OVER w from

(select poi,t1.ts as start_date,
t1.ts + '3 hour'::interval as end_date,
(select sum(apcpsfc)
from event_forecast_data t2
where t2.ts >= t1.ts
and t2.ts <= t1.ts + '3 hour'::interval and poi = t1.poi
group by poi
) as the_sum
from event_forecast_data t1
where ts > '2010-06-18 00:00:00' and ts + interval '3 hours' <= '2010-06-19
00:00:00'

group by poi,ts) as stats

WINDOW w AS (partition by poi order by the_sum desc)

order by poi,start_date

where initially I get the sum for all intervals of 3 hours of the day and
after with the window functions I get the row with the higher value ...

2010/6/17 stefano bonnin <stefano(dot)bonnin(at)gmail(dot)com>

> Hi all,
> I'm trying to make a query that, given N and a date, gives me the interval
> of N hours with the max(sum(...)). In others words, given the following
> table:
>
> 2010-06-16 00:00:00 | 0
> 2010-06-16 01:00:00 | 2
> 2010-06-16 02:00:00 | 1
> 2010-06-16 03:00:00 | 5
> 2010-06-16 04:00:00 | 7
> 2010-06-16 05:00:00 | 9
> 2010-06-16 06:00:00 | 2
> 2010-06-16 07:00:00 | 0
> 2010-06-16 08:00:00 | 0
> 2010-06-16 09:00:00 | 0
> 2010-06-16 10:00:00 | 1
> 2010-06-16 11:00:00 | 2
> 2010-06-16 12:00:00 | 1
> 2010-06-16 13:00:00 | 1
> 2010-06-16 14:00:00 | 1
> 2010-06-16 15:00:00 | 1
> 2010-06-16 16:00:00 | 1
> 2010-06-16 17:00:00 | 1
> 2010-06-16 18:00:00 | 1
> 2010-06-16 19:00:00 | 1
> 2010-06-16 20:00:00 | 1
> 2010-06-16 21:00:00 | 0
> 2010-06-16 22:00:00 | 3
> 2010-06-16 23:00:00 | 1
>
> With N = 3 and date = '2010-06-16' for example ... I'd like that the
> "query" gives me as response: the interval from 3AM and 5AM.
> Any solutions and/or hints?
>
> Thanks in advance.
> stefano
>