From: | "Andrey G(dot)" <andvgal(at)gmail(dot)com> |
---|---|
To: | Robert Haas <robertmhaas(at)gmail(dot)com> |
Cc: | pgsql-bugs(at)postgresql(dot)org |
Subject: | Re: BUG #5776: Unable to create view with parameter in PL/pgsql |
Date: | 2010-12-14 21:03:44 |
Message-ID: | AANLkTiksbHxpHTR03UAyB_y0eMFuyXYNwiZfVoFTMRmE@mail.gmail.com |
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Lists: | pgsql-bugs |
Robert,
Yes, you've read my mind about quote_literal() ;). The bug report is
rising exactly the parameter substitution issue.
Andrey
2010/12/14 Robert Haas <robertmhaas(at)gmail(dot)com>:
> On Mon, Dec 13, 2010 at 4:28 PM, Andrey G. <andvgal(at)gmail(dot)com> wrote:
>> It seems my original test, which also includes the EXECUTE approach,
>> has not come to you in full. EXECUTE statement also fails with
>> parameter: The test is attached in file.
>>
>> psql -q < db/db/pgbug_5776.sql
>> ERROR: there is no parameter $1
>> LINE 1: CREATE VIEW v4 AS SELECT * FROM t1 WHERE some_field = $1
>> ^
>> QUERY: CREATE VIEW v4 AS SELECT * FROM t1 WHERE some_field = $1
>> CONTEXT: PL/pgSQL function "bug_create_tmp_view_exec_test" line 3 at
>> EXECUTE statement
>
> Yeah, parameter substitution doesn't work in this case. You could
> however build up a string with quote_identifier() and then EXECUTE the
> resulting string.
>
> --
> Robert Haas
> EnterpriseDB: http://www.enterprisedb.com
> The Enterprise PostgreSQL Company
>
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