From: | Albe Laurenz <laurenz(dot)albe(at)wien(dot)gv(dot)at> |
---|---|
To: | "'David G(dot) Johnston *EXTERN*'" <david(dot)g(dot)johnston(at)gmail(dot)com> |
Cc: | "pgsql-general(at)postgresql(dot)org" <pgsql-general(at)postgresql(dot)org> |
Subject: | Re: psql doesn't pass on exported shell environment functions |
Date: | 2017-07-07 14:43:19 |
Message-ID: | A737B7A37273E048B164557ADEF4A58B53A80207@ntex2010i.host.magwien.gv.at |
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Thread: | |
Lists: | pgsql-general |
David G. Johnston wrote:
>> It works for me on Linux with 9.6.3 psql:
>
> Except you haven't recreated the scenario I presented.
>
> You only are involving a single script and that script defines "testfunction" itself
> (which makes exporting pointless). In my example the script being executed within the
> psql script does not define testfunction itself.
>
> -> == execute in subshell
>
> main-script (def func) -> psql -> psql-call-bash (invoke func)
I am confused; my shell script does *not* contain a function definition.
I copied and pasted a shell session:
First, show the script that contains a function invocation.
Then, define and export the function.
Then, call psql
Then, escape to a subshell.
Then, call the script that successfully calls the function.
Am I missing something?
Yours,
Laurenz Albe
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