From: | Zagato <zagato(dot)gekko(at)gmail(dot)com> |
---|---|
To: | "Ron Mayer" <rm_pg(at)cheapcomplexdevices(dot)com> |
Cc: | pgsql-general(at)postgresql(dot)org |
Subject: | Re: Interval Format |
Date: | 2008-11-22 02:28:49 |
Message-ID: | 98028b00811211828m2fdac1aq5be928ec819180f@mail.gmail.com |
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Thread: | |
Lists: | pgsql-admin pgsql-general |
Hi.. thanks for the answer.... well this work in the test sql, but this
needs to rewrite all the SQL in my PHP application :-p Jejej... can i set a
deatul time year in postgres.conf or with a single SET ... ?
Thanks..
Alan Acosta
On Fri, Nov 21, 2008 at 8:56 PM, Ron Mayer <rm_pg(at)cheapcomplexdevices(dot)com>wrote:
> Zagato wrote:
>
>> I have som SQL that in 8.0.3 do:
>> # SELECT '32 hours'::INTERVAL;
>> interval
>> -----------------
>> @ 1 day 8 hours
>>
>> And in 8.3.5 do:
>> seg_veh2=# SELECT '@ 32 hours'::INTERVAL;
>> interval
>> ------------
>> @ 32 hours
>>
>> Why i unable to get my old style of interval, i really need to see the day
>> part.... im using datestyle german in both.... im try with "SET
>> IntervalStyle TO..." but i get this error:
>>
>
> Even IntervalStyle won't help you here; since recent releases consider
> the values "1 day 8 hours" as distinct from "32 hours" (because
> they are at certain times of the year in some timezones
> where days are 25 hours, etc).
>
> So.. how can i recover my "days" part...
>>
>
> If you tell it what time of year you are thinking of this trick can work:
>
> dish=# set datestyle to german;
> SET
> dish=# select '2001-01-01'::timestamp + (interval '32 hours') -
> '2001-01-01'::timestamp;
> ?column?
> -----------------
> @ 1 day 8 hours
> (1 row)
>
>
>
>> Any help it appreciate... thanks :D
>>
>
>
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