Re: Why is table not found?

Hello Egon,

You created the table using delimited identifiers:

"Raum"

which is not the same as

Raum of raum or RAUM

When you use delimited identifiers (eg: "MyTable" instead of MyTable), the
name becomes case sensitive.

When you use SQL, you need to use delimited identifiers:

select * from "Raum"

With regards,

Martijn Tonies
Upscene Productions
http://www.upscene.com

Database Workbench - developer tool for Oracle, MS SQL Server, PostgreSQL,
SQL Anywhere, MySQL, InterBase, NexusDB and Firebird.

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I created a db 'Hausrat' with a table "Raum". If I look in pgadmin I
find the the table. In sql field is shown:

> -- Table: "Raum"
>
> -- DROP TABLE "Raum";
>
> CREATE TABLE "Raum"
> (
> "RaumID" serial NOT NULL, -- Automatisch vergebenes
Identifizierungsmerkmal für den Raum
> "Raum" character varying(15), -- Bezeichnung des Raums
> CONSTRAINT "Raum_pkey" PRIMARY KEY ("RaumID")
> )
> WITH (
> OIDS=FALSE
> );
> ALTER TABLE "Raum"
> OWNER TO egon;
> COMMENT ON COLUMN "Raum"."RaumID" IS 'Automatisch vergebenes
Identifizierungsmerkmal für den Raum';
> COMMENT ON COLUMN "Raum"."Raum" IS 'Bezeichnung des Raums';
>
>
> -- Index: "Raum_RaumID_idx"
>
> -- DROP INDEX "Raum_RaumID_idx";
>
> CREATE INDEX "Raum_RaumID_idx"
> ON "Raum"
> USING btree
> ("RaumID");
>
But psql tells me "Raum" is not existent:

> egon(at)xfEinzel ~ $ psql Hausrat
> psql (9.3.15)
> Type "help" for help.
>
> Hausrat=# SELECT * FROM Raum;
> ERROR: relation "raum" does not exist
> LINE 1: SELECT * FROM Raum;
> ^
> Hausrat=#

Why?

Egon

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