From: | Heikki Linnakangas <hlinnaka(at)iki(dot)fi> |
---|---|
To: | John Naylor <john(dot)naylor(at)enterprisedb(dot)com> |
Cc: | Greg Stark <stark(at)mit(dot)edu>, Amit Khandekar <amitdkhan(dot)pg(at)gmail(dot)com>, pgsql-hackers <pgsql-hackers(at)postgresql(dot)org> |
Subject: | Re: speed up verifying UTF-8 |
Date: | 2021-06-03 19:22:15 |
Message-ID: | 8f9ceae6-9d16-bb66-9292-a82cc8f150e4@iki.fi |
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Lists: | pgsql-hackers |
On 03/06/2021 22:16, Heikki Linnakangas wrote:
> On 03/06/2021 22:10, John Naylor wrote:
>> On Thu, Jun 3, 2021 at 3:08 PM Heikki Linnakangas <hlinnaka(at)iki(dot)fi
>> <mailto:hlinnaka(at)iki(dot)fi>> wrote:
>> > x1 = half1 + UINT64CONST(0x7f7f7f7f7f7f7f7f);
>> > x2 = half2 + UINT64CONST(0x7f7f7f7f7f7f7f7f);
>> >
>> > /* then check that the high bit is set in each byte. */
>> > x = (x1 | x2);
>> > x &= UINT64CONST(0x8080808080808080);
>> > if (x != UINT64CONST(0x8080808080808080))
>> > return 0;
>>
>> That seems right, I'll try that and update the patch. (Forgot to attach
>> earlier anyway)
>
> Ugh, actually that has the same issue as before. If one of the bytes is
> in one half is zero, but not in the other half, this fail to detect it.
> Sorry for the noise..
If you replace (x1 | x2) with (x1 & x2) above, I think it's correct.
- Heikki
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