From: | Steve Murphy <smurphy(at)intorrent(dot)com> |
---|---|
To: | "pgsql-general(at)postgresql(dot)org" <pgsql-general(at)postgresql(dot)org> |
Subject: | What is *wrong* with this query??? |
Date: | 2011-11-05 04:51:14 |
Message-ID: | 8DC625F671F9DF47B7B2ACBFA469B1040ED2670D@GMVEX02.gmvoices.com |
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Thread: | |
Lists: | pgsql-general |
I give! I'm flummoxed!
Here is what I have, 3 tables:
schedule
company building status0
3 x active
4 x active
5 x active
3 x active
3 x active
3 x active
In the end, I want to replace the building id's above. They start out with the non-informative value of '1';
company
id name status
3 x active
4 y active
5 z active
building
id company name
1 3 A active
2 3 B active
3 3 C active
4 4 D active
5 4 E active
6 4 F active
7 5 G active
8 5 H active
9 5 I active
So, every company has 3 schedules. Of the 3, I'd like to select the one with the lowest id.
I'm using postgresql 8.1. Yes, ancient, but I have no choice in this affair.
select schedule.id as sched_id, bld.id as bid
from
schedule
left join company on schedule.company = company.id
left join (select * from building where building.company = company.id order by id limit 1) as bld
where
schedule.status = 'active' and company.status = 'active' and bld.status = 'active';
I get a syntax error on the the "where".
ERROR: syntax error at or near "where" at character ….
LINE 6: where
^
If I leave out the where clause entirely, that's an error also,
ERROR: syntax error at or near ";" at character ….
LINE 5: … as bld ;
^ <it's right under the semicolon>
So, it's expecting ***SOMETHING*** after the "as bld", but it sure isn't going to tell me what.
What am I missing?
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