From: | "Hector Villarreal" <HVillarreal(at)mynewplace(dot)com> |
---|---|
To: | "Gary Stainburn" <gary(dot)stainburn(at)ringways(dot)co(dot)uk>, <pgsql-sql(at)postgresql(dot)org> |
Subject: | Re: join/group/count query. |
Date: | 2006-12-20 18:06:29 |
Message-ID: | 8C5B026B51B6854CBE88121DBF097A866A4A9D@ehost010-33.exch010.intermedia.net |
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Thread: | |
Lists: | pgsql-sql |
HI in reading this is it possible what was really intended :
Sum(case when o_model = 5 then 1 else NULL end) as KA
That would provide a count of all records meeting that condition.
Otherwise the count( approach will not do that.
-----Original Message-----
From: pgsql-sql-owner(at)postgresql(dot)org
[mailto:pgsql-sql-owner(at)postgresql(dot)org] On Behalf Of Gary Stainburn
Sent: Wednesday, December 20, 2006 8:20 AM
To: pgsql-sql(at)postgresql(dot)org
Subject: Re: [SQL] join/group/count query.
>
> And, I may be missing something, but I'm having a hard time
> understanding why you have all of those select columns of the form:
>
> count (case when o_model = 5 then 1 else NULL end) as KA,
>
> Considering that that can only return 1 or 0, the case statement would
do.
> Is it to avoid putting all of the column names in the group by clause?
> That's hackish and is as much or more typing.
>
> With regards to what you are actually trying to do, giving us your
table
> definitions and what you are trying to achieve would help a lot more
than
> just telling us the problem you are having. The column names in your
query
> are in no way descriptive and tell us nothing about your actual table
> structure.
The order_details view is a join of the orders table to the other
tables.
The order table contains the orders.
Each order has a business partner which is in a separate table. p_id is
the
key, p_name is the name of the partner.
Each order is for a single vehicle, which must be of a specific mode.
The
models are also stored in a separate table. o_model is the attribute in
the
orders table that contains the key to the models table.
The output I'm getting is below, which is what I want. For each partner
I get
a total followed by a breakdown by model the orders for the current
month.
key|p_id| p_name | total | ka | focus | c_max | s_max | fiesta |
fusion | mondeo | galaxy | ranger | connect | transit | fiesta_van
---+----+----------------+-------+----+-------+-------+-------+--------+
--------+--------+--------+--------+---------+---------+------------
40| 40|rrrrrrrrrrrrrrr | 2 |0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 1 | 1
|0
30| 30|rrrrr Group Plc | 2 |0 | 2 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0
|0
78| 78|rrrrr rrrrrrrrr | 2 |0 | 0 | 0 | 1 | 0 | 0 | 0 | 0 | 0 | 1 | 0
|0
46| 46|rrrrrrrrrrrr ) | 3 |0 | 1 | 0 | 0 | 1 | 0 | 0 | 0 | 0 | 1 | 0
|0
3| 3|eeeee | 8 |0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 2 | 2 | 4
|0
9| 9|eee | 3 |0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 1 | 0 | 2
|0
12| 12|qqqqqqqqqqqq |13 |0 | 0 | 0 | 0 | 0 | 0 | 2 | 0 | 0 | 5 | 6
|0
10| 10|rr Motor | 7 |0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 2 | 5
|0
34| 34|ffffff fffffff | 3 |0 | 0 | 0 | 0 | 0 | 0 | 1 | 0 | 0 | 0 | 2
|0
102| 102|xxxxxxxx xxxxxxx| 1 |0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 1 | 0 | 0
|0
--
Gary Stainburn
This email does not contain private or confidential material as it
may be snooped on by interested government parties for unknown
and undisclosed purposes - Regulation of Investigatory Powers Act, 2000
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