Re: quoting values magic

From: Alban Hertroys <dalroi(at)solfertje(dot)student(dot)utwente(dot)nl>
To: Brandon Metcalf <brandon(at)geronimoalloys(dot)com>
Cc: Jasen Betts <jasen(at)xnet(dot)co(dot)nz>, pgsql-general(at)postgresql(dot)org
Subject: Re: quoting values magic
Date: 2009-05-26 18:05:33
Message-ID: 87E8174C-B0CE-46D7-9338-055B4429DC9E@solfertje.student.utwente.nl
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On May 26, 2009, at 6:37 PM, Brandon Metcalf wrote:
> j> option 2: case when '$length' = '' ...
>
> j> you can use case like this:
>
> j> UPDATE foo
> j> SET
> j> pattern = '$pattern',
> j> shape = '$shape',
> j> length = case when '$length'='' then length else
> '$length' end,
> j> comment = '$comment'
> j> WHERE foo_id = $foo_id
>
> j> here you can substitute any value you choose for the empty string,
> j> 0 or NULL may (or may not) be more apropriate.
>
>
> The issue here is that these reduce back to my original problem. For
> example, if I use a CASE statement and I fall through to the ELSE,
> then the SQL is attempting to insert a "''" in a NUMERIC field which
> is not valid. That is, it's trying to do

No it doesn't, read that statement again ;)

If $length = 'foo' it reads (leaving out the extra fields):

UPDATE foo
SET length = CASE WHEN 'foo'='' THEN length ELSE 'foo' END
WHERE foo_id = $foo_id;

Which evaluates to:

UPDATE foo SET length = 'foo' WHERE foo_id = $foo_id;

Whereas if $length = '' it reads:

UPDATE foo
SET length = CASE WHEN ''='' THEN length ELSE '' END
WHERE foo_id = $foo_id

Which evaluates to:

UPDATE foo SET length = length WHERE foo_id = $foo_id

Alban Hertroys

--
If you can't see the forest for the trees,
cut the trees and you'll see there is no forest.

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