From: | Tom Lane <tgl(at)sss(dot)pgh(dot)pa(dot)us> |
---|---|
To: | "Mike G(dot)" <mike(at)thegodshalls(dot)com> |
Cc: | pgsql-bugs(at)postgresql(dot)org |
Subject: | Re: Substring function incorrect when searching for '@.' |
Date: | 2004-10-12 23:00:16 |
Message-ID: | 8170.1097622016@sss.pgh.pa.us |
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Lists: | pgsql-bugs |
"Mike G." <mike(at)thegodshalls(dot)com> writes:
> create a table with a data type of varchar (50) and name it email
> insert into this table the following values:
> test1(at)anyemail(dot)com
> Execute the following statement:
> SELECT CASE WHEN count(substring(email FROM '@.')) > 0 THEN count(substring(email FROM '@.')) ELSE 0 END, email FROM your_schema.your_table GROUP BY email;
> Result with be equal to 1 / True. It should be 0 / False.
This is not a bug; it's a POSIX regular expression match, and it's
behaving exactly as it should ('.' matches any character).
The particular syntax substring(char-expression FROM char-expression)
is not defined by SQL99 --- their regular-expression construct requires
a third parameter (ESCAPE something). We have chosen to interpret it
as a POSIX regular-expression match. See
http://www.postgresql.org/docs/7.3/static/functions-matching.html
regards, tom lane
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