From: | Michael Glaesemann <grzm(at)seespotcode(dot)net> |
---|---|
To: | Michael Glaesemann <grzm(at)seespotcode(dot)net> |
Cc: | Andrew Sullivan <ajs(at)crankycanuck(dot)ca>, pgsql-sql(at)postgresql(dot)org |
Subject: | Re: current_date / datetime stuff |
Date: | 2007-06-04 16:39:21 |
Message-ID: | 7B00D29F-089A-4A19-B9C1-0FF8A949DDA3@seespotcode.net |
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Thread: | |
Lists: | pgsql-sql |
On Jun 4, 2007, at 10:59 , Michael Glaesemann wrote:
>
> On Jun 4, 2007, at 10:27 , Andrew Sullivan wrote:
>
>> On Mon, Jun 04, 2007 at 10:04:37AM -0500, Joshua wrote:
>>> that will return the date of the first Monday of the month?
>>
>> I guess you need to write a function to do this. I suppose you could
>> do it by finding out what day of the week it is and what the date is,
>> then counting backwards to the earliest possible Monday.
>
> As Andrew said, there's no built-in function to do this, but it's
> easy enough to write one. Here's a rough example (very lightly
> tested and probably overly complicated)
And a little simpler:
CREATE OR REPLACE FUNCTION first_dow_of_month(DATE, INTEGER)
RETURNS DATE
IMMUTABLE
LANGUAGE SQL AS $_$
SELECT v_first_day_of_month + ( 7 + $2 - v_day_of_week) % 7
AS first_dow_of_month
FROM (
SELECT v_first_day_of_month
, extract('dow' from v_first_day_of_month)::integer
AS v_day_of_week
FROM (SELECT date_trunc('month', $1)::date)
AS mon(v_first_day_of_month)) as calc;
$_$;
CREATE OR REPLACE FUNCTION first_monday(DATE)
RETURNS DATE
IMMUTABLE
LANGUAGE SQL AS $_$
SELECT first_dow_of_month($1, 1);
$_$;
Michael Glaesemann
grzm seespotcode net
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