shell script to populate array values

Hello,

I would like to create a shell script that would populate two variables with
the return of a SELECT statement that would return two attributes...

For example...

#!/bin/bash
SERVER_NAMES=`psql Admin -Upostgres -hMYSERVER -t -c"SELECT servername,
instanceport from server where serverclass = 3 and isactive = 'True' ";`

As you can see, I'm returning the servername "and" the instanceport from the
server table. This will later allow me to create psql commands to connect
to each server dynamically.

I had the script working correctly when I was just running it for the server
name as below...
#!/bin/bash
SERVER_NAMES=`psql Admin -Upostgres -hMYSERVER -t -c"SELECT servername from
server where serverclass = 3 and isactive = 'True' ";`

Does anyone know the easiest way to get both values out of some variables
that I could set?

Later in the script, I'm creating a for loop and iterating through the
server names and would like to build connection strings dynamically with the
results from the select string...

for i in $SERVER_NAMES
do
psql -Upostgres -h$i -p$i -A -t -c"SELECT '$i', '$BATCHTIME', name,
setting, category, short_desc, context, vartype, source, min_val, max_val
FROM pg_settings;" | psql Admin -Upostgres -hMYSERVER -t -c"COPY
serverconfigsetting FROM STDIN WITH DELIMITER '|' NULL AS '';"
echo "Done with $i"
done

As you can see I have "-h$i -p$i" in the script for the host and port.
Again the script worked fine when I just had the -h(at)i in there...

I know that the current forloop is incorrect specifiying the $i twice but I
just put that in there to show an example of what I was hoping to do... It
would probably be more accessing the array value like -h$i[0:0] -p$i[0:1] in
pseudo code for accessing array values.

Thanks in advance,

Paul

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