Robert Haas <robertmhaas(at)gmail(dot)com> writes:
> On Thu, May 27, 2010 at 3:35 PM, Tom Lane <tgl(at)sss(dot)pgh(dot)pa(dot)us> wrote:
>> If the function is a cast function (which it is),
> I don't think it is.
It certainly is --- he was actually declaring a cast with it in his
example, no?
regards, tom lane