Re: How to \ef a function ?

On 1/8/24 08:26, David Gauthier wrote:
> atletx7-reg017:/home/dgauthie[ 120 ] --> dvdbdev
> Pager usage is off.
> psql (11.5, server 11.3)
> Type "help" for help.
>
> dvdb=# \df opid.bef_ins_axi_reqs_set_trig;
>                                  List of functions
>  Schema |           Name            | Result data type | Argument data
> types | Type
> --------+---------------------------+------------------+---------------------+------
>  opid   | bef_ins_axi_reqs_set_trig | trigger          |
>       | func
> (1 row)
>
> dvdb=# \ef opid.bef_ins_axi_reqs_set_trig;
> ERROR:  function "opid.bef_ins_axi_reqs_set_trig;" does not exist

Lose the ';'.

It should be:

\ef opid.bef_ins_axi_reqs_set_trig

> dvdb=# \ef opid.bef_ins_axi_reqs_set_trig();
> ERROR:  expected a right parenthesis
> dvdb=#
>
> So the function exists with \df but not \ef ?
> I get the need to identify the argument list (in case there's >1 with
> same name, diff arg list), but '()' doesn't work.  Does this have to do
> with the returned trigger type ?
>

--
Adrian Klaver
adrian(dot)klaver(at)aklaver(dot)com