From: | Tom Lane <tgl(at)sss(dot)pgh(dot)pa(dot)us> |
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To: | Bruno Wolff III <bruno(at)wolff(dot)to> |
Cc: | Christopher Kings-Lynne <chriskl(at)familyhealth(dot)com(dot)au>, Virgile Beddok <virgile(dot)beddok(at)igd(dot)fraunhofer(dot)de>, pgsql-novice(at)postgresql(dot)org, pgsql-advocacy(at)postgresql(dot)org, pgsql-admin(at)postgresql(dot)org |
Subject: | Re: [NOVICE] [pgsql-advocacy] Function which gives back the nearest neighbours |
Date: | 2005-03-27 16:32:12 |
Message-ID: | 5796.1111941132@sss.pgh.pa.us |
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Lists: | pgsql-admin pgsql-advocacy pgsql-novice |
Bruno Wolff III <bruno(at)wolff(dot)to> writes:
> On Sun, Mar 27, 2005 at 13:24:34 +0800,
> Christopher Kings-Lynne <chriskl(at)familyhealth(dot)com(dot)au> wrote:
>>> I'm looking for an existing function which allows me to search the nearest
>>> neighbours of the requested value.
>>
>> Well you could try something like:
>>
>> SELECT * FROM table ORDER BY ABS(val - 2) LIMIT 1;
>>
>> That doesn't get you all the way there, but it's an idea...
> For multidimensional objects you can do the same thing with a distance
> metric function. It will be relatively slow since this won't be indexable
> and will require a sort of all of the values. If you have some bound on
> how far apart points can be, then you might be able to limit the set
> of candidate points using an indexable search.
I'd probably go with looking for the nearest "above" neighbor and
nearest "below" neighbor separately, eg
select * from tab where val > 'target' order by val limit 1;
select * from tab where val < 'target' order by val desc limit 1;
If there's an index on val, this should work really well. Of course, if
"nearest" is being defined in multidimensional terms as Bruno is
imagining, it doesn't work at all...
BTW, why is this thread cross-posted to so many lists? It seems
off-topic for at least two of 'em.
regards, tom lane
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