| From: | Joe Conway <mail(at)joeconway(dot)com> | 
|---|---|
| To: | "David G(dot) Johnston" <david(dot)g(dot)johnston(at)gmail(dot)com>, "dominik(dot)kosiorek(at)infobright(dot)com" <dominik(dot)kosiorek(at)infobright(dot)com> | 
| Cc: | "pgsql-bugs(at)postgresql(dot)org" <pgsql-bugs(at)postgresql(dot)org> | 
| Subject: | Re: BUG #13934: wrong result of split_part with char value | 
| Date: | 2016-02-09 15:29:08 | 
| Message-ID: | 56BA05C4.7010004@joeconway.com | 
| Views: | Whole Thread | Raw Message | Download mbox | Resend email | 
| Thread: | |
| Lists: | pgsql-bugs | 
On 02/08/2016 06:00 PM, David G. Johnston wrote:
> On Monday, February 8, 2016, <dominik(dot)kosiorek(at)infobright(dot)com
> This calls for another round of "don't use char” advice...
> 
> It is not a bug but a result of the fact that trailing white space in
> char values is able to be trimmed away thus leaving you the empty string
> and no splitting.
In other words, when you insert ' ' into string1postgres.a3pattern,
which is defined as char(15), the single space is trimmed leaving an
empty string:
test=# select '***' || a3pattern || '!!!' from string1postgres;
 ?column?
----------
 ***!!!
(1 row)
And if you feed an actual space to split_part(), it works as expected.
test=# select split_part(a2,' ',a4field) from string1postgres;
 split_part
------------
 abcd
(1 row)
HTH,
Joe
-- 
Crunchy Data - http://crunchydata.com
PostgreSQL Support for Secure Enterprises
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