From: | Håkan Jacobsson <hakan(dot)jacobsson(at)relevanttraffic(dot)com> |
---|---|
To: | Adam Rich <adam(dot)r(at)sbcglobal(dot)net>, "pgsql-general(at)postgresql(dot)org" <pgsql-general(at)postgresql(dot)org> |
Subject: | Re: Getting the count(*) from two tables and two date ranges in same query |
Date: | 2008-01-28 14:48:15 |
Message-ID: | 5580CB5EB883C44587BC48FA0E54592223E4E143F5@RTSRV02.relevanttraffic.local |
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Thread: | |
Lists: | pgsql-general |
Hi Adam and all,
I don't get it=). How do I input the second daterange in this query?
Also, I have the ID from table1. Its known in the query.
Wouldn't I need to use a UNION for this kind of query?
Håkan Jacobsson - System Developer
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Från: Adam Rich [mailto:adam(dot)r(at)sbcglobal(dot)net]
Skickat: den 28 januari 2008 15:22
Till: Håkan Jacobsson; pgsql-general(at)postgresql(dot)org
Ämne: RE: [GENERAL] Getting the count(*) from two tables and two date ranges in same query
> Resulting in 4 columns in the ResultSet like:
>
> count(*)_from_table2_between_fromdate1_and_todate1 = X
> count(*)_from_table2_between_fromdate2_and_todate2 = Y
> count(*)_from_table3_between_fromdate1_and_todate1 = Z
> count(*)_from_table3_between_fromdate2_and_todate2 = V
>
> Is this possible?
Select t1.id,
sum(case when t2.date between d1 and d2 then 1 else 0 end) as sum1,
sum(case when t3.date between d1 and d2 then 1 else 0 end) as sum2
from t1, t2, t3
where t1.id=t2.id and t2.id = t3.id
group by t1.id
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