Re: way to custom sort column by fixed strings, then by field's content

From: Adrian Klaver <adrian(dot)klaver(at)gmail(dot)com>
To: Susan Cassidy <susan(dot)cassidy(at)decisionsciencescorp(dot)com>, "pgsql-general(at)postgresql(dot)org" <pgsql-general(at)postgresql(dot)org>
Subject: Re: way to custom sort column by fixed strings, then by field's content
Date: 2014-02-03 19:14:11
Message-ID: 52EFEA83.90801@gmail.com
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On 02/03/2014 10:53 AM, Susan Cassidy wrote:
> I have a column that contains items like
> 'absolute root'
> 'root 3'
> 'root 4'
> 'root 5'
> 'scene 1'
> 'scene 2'
> 'scene 3'
>
> and I would like them to sort in that order.
>
> I tried:
> select sti.description, sc.description from scene_thing_instances sti
> join scenes sc on sti.scene_id = sc.scene_id
> order by CASE sc.description
> when (sc.description = 'absolute root'::text) then 1
> when (sc.description ilike 'root%') then 2
> else 3
> END;
>
> I was starting with this, and was going to add perhaps another case
> statement.
>
> But it gives me:
> ERROR: operator does not exist: text = boolean
> LINE 3: when (sc.description = 'absolute root'::text) th...
> ^
> HINT: No operator matches the given name and argument type(s). You
> might need to add explicit type casts.
>
> I don't understand this because description is a text column, not
> boolean, and certainly 'absolute root'::text is a text string.
>
> This is 9.2.
>
> Ideas, anyone?

select sti.description, sc.description from scene_thing_instances sti
join scenes sc on sti.scene_id = sc.scene_id
order by sc.description, CASE
when (sc.description = 'absolute root'::text) then 1
when (sc.description ilike 'root%') then 2
else 3
END;

>
> Thanks,
> Susan

--
Adrian Klaver
adrian(dot)klaver(at)gmail(dot)com

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