From: | Michael Glaesemann <grzm(at)seespotcode(dot)net> |
---|---|
To: | "Josh Tolley" <eggyknap(at)gmail(dot)com> |
Cc: | danmcb <danielmcbrearty(at)gmail(dot)com>, pgsql-general(at)postgresql(dot)org |
Subject: | Re: finding items with 0 rels for a 0 to many relationship |
Date: | 2007-06-21 17:13:38 |
Message-ID: | 4F410D2A-F8AA-46B2-BD9E-594893764201@seespotcode.net |
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Lists: | pgsql-general |
On Jun 21, 2007, at 11:57 , Josh Tolley wrote:
> On 6/21/07, danmcb <danielmcbrearty(at)gmail(dot)com> wrote:
>> Hi
>>
>> I have two tables, say A and B, that have a many-to-many
>> relationship, implemented in the usual way with a join table A_B.
>>
>> How can I economically find all the rows in table A whose id's are
>> not
>> in A_B at all (i.e. they have zero instances of B associated)?
>
> Use a left join. For instance, say there are a.id and b.id columns,
> which are the primary keys in A and B respectively. Also say A_B
> contains columns aid and bid which reference a.id and b.id
> respectively.
>
>> SELECT * FROM A LEFT JOIN A_B ON (A.ID = A_B.AID) WHERE A_B.BID IS
>> NULL;
Alternatively you can use EXCEPT. Using Josh's schema:
SELECT id
FROM A
EXCEPT
SELECT aid
FROM A_B.
You'll want to check with EXPLAIN ANALYZE, but in general I suspect
the outer join is faster.
Michael Glaesemann
grzm seespotcode net
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