From: | Craig Ringer <ringerc(at)ringerc(dot)id(dot)au> |
---|---|
To: | Adarsh Sharma <adarsh(dot)sharma(at)orkash(dot)com> |
Cc: | pgsql-general General <pgsql-general(at)postgresql(dot)org> |
Subject: | Re: Select latest Timestamp values with group by |
Date: | 2011-10-10 13:23:16 |
Message-ID: | 4E92F1C4.9060005@ringerc.id.au |
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Lists: | pgsql-general |
On 10/10/2011 08:32 PM, Adarsh Sharma wrote:
> Dear all,
>
> I need to write a query to select latest rows with timestamp values.
> My ID is repeated with lat lon and timestamp. I want the latest row of
> each ID ( group by id ).
[snip]
> "3911";"661000212";26.8491101532852;92.8058205131302;0;"2011-10-14
> 12:47:33.360572"
>
>
> Can anyone let me know the query for that.
No, they can't. You only posted semicolon-separated data, not a schema
with column names or anything much else.
For a task like this you can use a window function, or you can self-join
and use a WHERE clause to match the greatest row. Using a window
function will be MUCH more efficient, so only use the self-join if
you're running on a really old version of PostgreSQL.
http://www.postgresql.org/docs/9.0/static/tutorial-window.html
http://www.postgresql.org/docs/9.0/static/functions-window.html
Using the first_value or last_value window functions with an ordering
clause to select the greatest timestamp within each window frame.
http://www.postgresql.org/docs/9.0/static/functions-window.html#FUNCTIONS-WINDOW-TABLE
--
Craig Ringer
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