Creating a query to structure results grouped by two columns, pivoting only a third colum

Hello there,
In order to achieve such structure "pivoting" table and "grouping by" multiple columns. (i.e. as illustrated below), what would be the SQL implementation?
The source query is:

````
SELECT
t1.date,
t1.area,
t1.canal,
SUM(t1.peso) AS peso
FROM table1 t1
GROUP BY 1, 2, 3
ORDER BY 1, 2, 3

````

and source query generates a initial structure as in:

###########################
date | area | canal | peso
2021-03-01 area1 can1 45.6768
2021-03-01 area1 can2 54.6768
2021-03-01 area1 can3 87.6
2021-03-01 area2 can1 1.87
2021-03-01 area2 can2 12.7687
2021-03-01 area2 can3 965.568
2021-03-01 area3 can1 968.95
2021-03-01 area3 can2 1.6867
2021-03-01 area3 can3 8.897
…. … … ...
2021-06-01 area1 can1
2021-06-01 area1 can2
2021-06-01 area1 can3
2021-06-01 area2 can1
… … ...

2021-12-01 area1
2021-12-01 area1
2021-12-01 area1
###########################

Then, the goal's to achieve a final structure grouped by columns "area" and "canal", pivoting column “date", but only to the column "peso".
Plus, a partial total of each area, named as "total” .

I tried to write a query to support such a display, however, I got stuck at pivoting date only to the column peso

````
SELECT
t2.area,
t2.canal,
( SELECT
month,
peso_valor
FROM (
SELECT
month(t1.date) month,
t1.area,
t1.canal,
SUM(t1.peso_valor) AS peso_valor
FROM tbl_data t1
GROUP BY 1, 2, 3
ORDER BY 1, 2, 3
) source_table
) PIVOT (
peso
FOR month IN (
1 Jan, 2 Feb, 3 Mar, 4 Apr, 5 Mai, 6 Jun, 7 Jul, 8 Aug, 9 Sep, 10 Oct, 11 Nov, 12 Dec
)
) as pivot_table
ORDER BY month
) as t2.peso
FROM tbl_data t2
GROUP BY 1, 2
````

what would be the SQL implementation to achieve a structure as such ?
(.i.e. grouped by columns "area" and "canal", pivoting column “date", but only to the column "peso”.)

illustrated bellow?

Best wishes,
I

###########################
area | canal | 2021-03-01 | 2021-04-01 | 2021-05-01 | 2021-06-01 | ...
peso peso peso peso

area1 can1 45.6768 875.98 1.232 …
area1 can2 54.6768 665.8 2.43 ...
area1 can3 87.6 65.8 4.76 ...
area1 total SUM(45.6768+54.6768+87.6) SUM(875.98+665.8+65.8) SUM(1.232+2.43+4.76) ...

area2 can1 1.87 … ...
area2 can2 12.7687
area2 can3 965.568
area2 total SUM(1.87+12.7687+965.568) … ...

area3 can1 968.95
area3 can2 1.6867
area3 can3 8.897

...
###########################