Re: ALL() question

Julien Cigar escreveu:
> Hello,
>
> I have a problem with the ALL() subquery expression.
> I have three tables:
> - specimens
> - test_bits
> - specimen_test_bits
>
> The specimen_test_bits table contains two foreign keys, one to
> specimens(id), another to test_bits(id).
>
> Here is an output of specimen_test_bits:
>
> muridae=> select * from specimen_test_bits;
> specimen_id | test_bit_id
> -------------+-------------
> 46096 | 1
> 46096 | 2
> 46096 | 3
> 46096 | 4
> 52894 | 1
> 52894 | 3
> 12546 | 2
>
> What I would like is a query that returns all the specimen_id of
> this table which have _all_ the given test_bit_id. So in this
> case, with test_bit_id 1,2,3,4 it should return only
> specimen_id 46096.
>
> With the following I got a syntax error:
> select specimen_id
> from specimen_test_bits
> where test_bit_id = all(1,2,3,4);
>
> The following works but no rows are returned :
> select specimen_id
> from specimen_test_bits
> where test_bit_id = all(select id from test_bits where id in (1,2,3,4));
>
> Any idea how I could do this ? I guess the problem is my ALL() expression ...
>

Unclear, but works...

SELECT DISTINCT stb.specimen_id FROM specimen_test_bits stb
WHERE NOT EXISTS (SELECT * FROM (VALUES (1), (2), (3) ,
(4)) AS foo(id)
WHERE NOT EXISTS (SELECT
stb1.test_bit_id FROM specimen_test_bits stb1
WHERE foo.id =
stb1.test_bit_id
AND
stb.specimen_id = stb1.specimen_id));

Osvaldo