Re: Format intervall as hours/minutes etc

Andreas Joseph Krogh wrote:
> On Sunday 16 September 2007 13:14:27 Andreas Kretschmer wrote:
>> Andreas Joseph Krogh <andreak(at)officenet(dot)no> schrieb:
>>> Hi all. Any hint on how to format this interval as number of hour/seconds
>>> etc? select age('2007-09-22 17:00'::timestamp, '2000-02-20
>>> 18:00'::timestamp); age
>>> -------------------------------
>>> 7 years 7 mons 1 day 23:00:00
>> You can use extract(epoch, from ...) like this:
>>
>> test=*# select extract(epoch from '2007-09-22 17:00'::timestamp) - extract
>> (epoch from '2000-02-20 18:00'::timestamp); ?column?
>> -----------
>> 239407200
>> (1 row)
>>
>> Now you can calculate the hours and so on.
>
> Yes, this works fine for dates >= 1970, but I'm looking for a more general
> solution which takes an arbitrary interval as input. The reason why I'm using
> PG to calculate this is 'cause it takes 25/23 hour days, leapyears etc. into
> account when calculating intervals.

Is that all you use it for?? ;-)

You may want to add the timezone to get the effect of daylight savings.

postgres=# select age('2007-03-25 7:00:00'::timestamptz, '2007-03-25
1:00:00'::timestamptz);
age
----------
06:00:00
(1 row)

postgres=# select age('2007-03-25 7:00:00+9:30'::timestamptz,
'2007-03-25 1:00:00+9:30'::timestamptz);
age
----------
05:00:00
(1 row)

I haven't used intervals much so I may be missing something.

I get the idea you want the interval to be expressed as 2,765 days and
23 hours or 66,383 hours, which I think would be useful (more so for
shorter intervals).

I am thinking the exact function you are after isn't there - from what I
can find a larger interval is always given as x years y months z days...
which is why extracting the epoch is the easiest point to start your calcs.

Maybe this can be a feature request - functions to give an interval in
total number of days/hours/minutes instead of years months days

--

Shane Ambler
pgSQL(at)Sheeky(dot)Biz

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