From: | Tom Allison <tom(at)tacocat(dot)net> |
---|---|
To: | "Uwe C(dot) Schroeder" <uwe(at)oss4u(dot)com> |
Cc: | pgsql-general(at)postgresql(dot)org, Lew <lew(at)lewscanon(dot)nospam> |
Subject: | Re: CASE in ORDER BY clause |
Date: | 2007-07-20 11:25:51 |
Message-ID: | 46A09BBF.9050902@tacocat.net |
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Lists: | pgsql-general |
Uwe C. Schroeder wrote:
>
> On Saturday 07 July 2007, Lew wrote:
>
>> So if your RDBMS sorts NULLs after all other values, then from
>>
>>>> select start_date from show_date
>>>> order by
>>>> case when start_date > CURRENT_DATE then start_date end desc,
>>>> case when start_date <= CURRENT_DATE then start_date end asc;
>> all rows with start_date > CURRENT_DATE will appear first, in start_date
>> descending order,
>> then all rows with start_date <= CURRENT_DATE will appear, in start_date
>> ascending order.
>>
>> Is CURRENT_DATE evaluated once for the query or twice for each row?
>
> CURRENT_DATE is evaluated once per transaction. If you run in autocommit -
> mode, then the single query is wrapped in a transaction by itself.
> Either way it's never evaluated per occurrence.
>
I'm coming in late on this but you might try something like...
select ... from (
select
...
case when start_date > current date
then 1 || start_date - current_date
else 0 || current_date - start_date end "FOO"
)
order by FOO desc
Or something like that...
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