Re: avg(interval)

Well, the query is working ok numerically, but should the answer really
be reported as 4 days and 33 hours?

Erik

Aaron Bono wrote:
> Right, the 23 is just less than 1 day, not 23 days.
>
> The good news: your query is working!
>
> -Aaron
>
> On 6/26/06, *Joe* < dev(at)freedomcircle(dot)net
> <mailto:dev(at)freedomcircle(dot)net>> wrote:
>
> Tom Lane wrote:
> > "Jeremiah Elliott" < geek00(at)gmail(dot)com <mailto:geek00(at)gmail(dot)com>>
> writes:
> >> however if i don't average them here is what i get:
> >> "7 days 22:24:50.62311";"*2420"
> >> "9 days 22:21: 02.683393";"*2420"
> >> "23:21:35.458459";"*2420"
> >> "4 days 22:47:41.749756";"*2420"
> >> "3 days 06:05:59.456947";"*2420"
> >
> >> which should average to just over nine days -
> >
> > Uh ... how do you arrive at that conclusion? I haven't done the
> math,
> > but by eyeball an average of four-something days doesn't look
> out of
> > line for those values.
>
> It seems he's calculating (7 + 9 + 23 + 4 + 3) / 5 ...
>
> Joe
>

--
erik jones <erik(at)myemma(dot)com>
software development
emma(r)