From: | Jim Johannsen <jjsa(at)gvtc(dot)com> |
---|---|
To: | |
Cc: | "Pgsql-sql(at)postgresql(dot)org" <Pgsql-sql(at)postgresql(dot)org> |
Subject: | Re: How to get a count() where column < ''? |
Date: | 2005-12-04 22:17:40 |
Message-ID: | 43936B04.3010006@gvtc.com |
Views: | Raw Message | Whole Thread | Download mbox | Resend email |
Thread: | |
Lists: | pgsql-sql |
Joost Kraaijeveld wrote:
>Hi Stephan,
>
>On Sun, 2005-12-04 at 13:33 -0800, Stephan Szabo wrote:
>
>
>>>SELECT COUNT(customers.objectid) FROM prototype.customers,
>>>prototype.addresses
>>>WHERE
>>>customers.contactaddress = addresses.objectid
>>>AND
>>>zipCode < '2716BN'
>>>ORDER By zipCode, houseNumber
>>>
>>>
>
>
>
>>In a non-grouped query like the above, I don't think that the order by is
>>meaningful. You only get one row back anyway without a group by, and
>>there's no single zipCode or houseNumber to associate with the row.
>>
>>
>>
>What do you mean by a non-grouped query? The query below gives the same
>error:
>
>SELECT zipcode, COUNT(*) FROM prototype.customers, prototype.addresses
>WHERE
>customers.contactaddress = addresses.objectid
>AND
>zipCode < '2716BN'
>
>
>
Try
SELECT COUNT(*)
FROM prototype.customers, prototype.addresses
WHERE customers.contactaddress = addresses.objectid
AND zipCode < '2716BN'
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