Re: division by zero issue

Doh...,

I messed up

This might work better.

SELECT
tasks.task_id,
CASE
WHEN task_count = '0'
THEN '0'::int4
ELSE (task_duration * task_duration_type / task_count)
END as hours_allocated
FROM
(
SELECT
FROM tasks
LEFT JOIN user_tasks
ON tasks.task_id = user_tasks.task_id
WHERE tasks.task_milestone = '0'
GROUP BY
tasks.task_id,
task_duration,
task_duration_type
) as intermediate;

Greg Donald wrote:

>On Wed, 15 Sep 2004 14:01:23 -0400, Tom Lane <tgl(at)sss(dot)pgh(dot)pa(dot)us> wrote:
>
>
>>You need to put it in HAVING, instead.
>>
>>Note also this 7.4.4 bug fix:
>>
>>* Check HAVING restriction before evaluating result list of an aggregate plan
>>
>>which means that this isn't really gonna work unless you are on 7.4.5.
>>(It's fairly astonishing that no one noticed we were doing this in the
>>wrong order until recently, but no one did ...)
>>
>>
>
>Thanks, you guys are so helpful.
>
>This works great on my workstation with 7.4.5. But what's the 7.2 way
>of doing it? Our production server is a bit older.
>
>I also tried Mr Fraser's suggestion:
>
>SELECT
> tasks.task_id,
> CASE
> WHEN task_count = '0'
> THEN '0'::int4
> ELSE (task_duration * task_duration_type / task_count) as hours_allocated
> END
>FROM
>(
> SELECT
> FROM tasks
> LEFT JOIN user_tasks
> ON tasks.task_id = user_tasks.task_id
> WHERE tasks.task_milestone = '0'
> GROUP BY
> tasks.task_id,
> task_duration,
> task_duration_type
>) as intermediate;
>
>but it's producing an error near the AS for some reason I can't tell.
>I tried wrapping it with some parentheses but it didn't help.
>
>TIA..
>
>
>

--
Guy Fraser
Network Administrator
The Internet Centre
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