Re: format return of "age" to hh:mm

On 3/5/20 7:50 AM, David Gauthier wrote:
> Hi:
>
> How does one reformat the output of the "age" function to always be in
> terms of hours:mins.
>
> E.g.
>
> dvdb=> select age('2020-03-05 01:40:32-05','2020-03-01 21:56:05-05');
>        age
> -----------------
>  3 days 03:44:27
> (1 row)
>
> I want...
>
> "75:44"
>
> I'm not married to "age"  If there's a better way to do this that's fine
> too.

Not sure it's better, but it will give you idea of what needs to be done:

SELECT
floor(
extract(
epoch FROM ('2020-03-05 01:40:32-05'::timestamptz -
'2020-03-01 21:56:05-05'::timestamptz))
/ 3600)::varchar || ':' ||
((mod(
extract(
epoch FROM ('2020-03-05 01:40:32-05'::timestamptz -
'2020-03-01 21:56:05-05'::timestamptz))::numeric,
3600::numeric) / 60)::int)::varchar;

?column?
----------
75:44
(1 row)

>
> Thanks in advance !

--
Adrian Klaver
adrian(dot)klaver(at)aklaver(dot)com