From: | Robby Russell <rrussell(at)commandprompt(dot)com> |
---|---|
To: | pgsql-php(at)postgresql(dot)org |
Cc: | Yasmine Kedoo <yazkedoo(at)hotmail(dot)com> |
Subject: | Re: UPDATE - Changing Password |
Date: | 2004-04-17 21:40:24 |
Message-ID: | 4081A448.4070204@commandprompt.com |
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Lists: | pgsql-php |
Yasmine Kedoo typed this on 04/17/2004 02:28 PM:
> Hi.
>
> Does anyone know how to use UPDATE with PHP for changing a password?
> I've tried the following code:
>
> $query = "UPDATE patperinfo SET trim(password)='$newpw' WHERE
> trim(gpid)='$gpidno'";
> $result = pg_exec($database, $query);
>
> where new $newpw & $gpidno are the values entered into a form then
> passed to the script.
>
> I get the following error:
>
> Warning: PostgreSQL query failed: ERROR: parser: parse error at or near
> "(" at character 27 in /home/webpages/yamkedoo/Tests/chpw1.php on line 48
>
> where the error is on the line: $result = pg_exec($database, $query);
>
>
$query = "UPDATE tablename SET password = '$newpw' WHERE ...
I don't know why you'd trim a fieldname while setting it.
-Robby
--
Robby Russell, | Sr. Administrator / Lead Programmer
Command Prompt, Inc. | http://www.commandprompt.com
rrussell(at)commandprompt(dot)com | Telephone: (503) 667.4564
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