Re: 7.3 "group by" issue

On 21 Feb 2003 at 13:00, Chad Thompson wrote:

> > On 21 Feb 2003 at 19:18, Gaetano Mendola wrote:
> >
> > > > Hi folks,
> > > >
> > > > This query:
> > > >
> > > > SELECT element_id as wle_element_id, COUNT(watch_list_id)
> > > > FROM watch_list JOIN watch_list_element
> > > > ON watch_list.id = watch_list_element.watch_list_id
> > > > AND watch_list.user_id = 1
> > > > GROUP BY watch_list_element.element_id
> > >
> > > Try:
> > >
> > > SELECT element_id as wle_element_id, COUNT(watch_list_id)
> > > FROM watch_list JOIN watch_list_element
> > > ON watch_list.id = watch_list_element.watch_list_id
> > > WHERE
> > > watch_list.user_id = 1
> > > GROUP BY watch_list_element.element_id
> >
> > ERROR: Attribute unnamed_join.element_id must be GROUPed or used in
> > an aggregate function
> >
>
> I think that the wrong problem was solved here. Items in the order by
> clause must be in the target list.
>
> heres what it says in the docs
> *The ORDER BY clause specifies the sort order:
>
> *SELECT select_list
> * FROM table_expression
> * ORDER BY column1 [ASC | DESC] [, column2 [ASC | DESC] ...]
> *column1, etc., refer to select list columns. These can be either the output
> name of a column (see Section 4.3.2) or the number of a column. Some
> examples:
>
> Note that "column1, etc., refer to select list"

I don't see how ORDER BY enters into this situation. It's not used.
What are you saying?
--
Dan Langille : http://www.langille.org/