Re: novice, question

Andy Arledge wrote:
>
> anyone have an idea why this won't work? when i print out "i" it says 893,
> but it should be 41. and the values are null for the array $userinfo.
>
> thanks in advance,
>
> andy arledge
>
> if(!($result= pg_exec($link, "SELECT * from signup, info1, info2 where
> (signup.username='$uname' or
> info1.username='$uname' or
> info2.username='$uname');"))){
> DisplayErrMsg(sprintf("Error in executing line %s stmt",
> $selectStmt));
> exit();
> }
> for($i = 0; $userinfo = @pg_fetch_object($result, $i); $i++);

Why is there an '@' in front of that pg_fetch_object call?

Cheers,
Andrew.
--
_____________________________________________________________________
Andrew McMillan, e-mail: Andrew(at)catalyst(dot)net(dot)nz
Catalyst IT Ltd, PO Box 10-225, Level 22, 105 The Terrace, Wellington
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