Re: [SQL] Finding the "most recent" rows

I don't think you can be using 6.5 even if you think you are. Make sure
you have 6.5 and everything is pointing to 6.5 including postmaster.

Chairudin Sentosa wrote:
>
> I tried this, and did not work.
>
> ibs=> select * from ibs_billing_record order by start_time desc limit 2;
> ERROR: parser: syntax error at or near "limit"
>
> Regards,
> Chai
>
> Michael J Davis wrote:
>
> > Try
> > select * from the_place order by the_time desc limit 2;
> >
> > -----Original Message-----
> > From: Chris Bitmead [SMTP:chris(dot)bitmead(at)bigfoot(dot)com]
> > Sent: Thursday, April 22, 1999 8:45 AM
> > To: pgsql-sql(at)postgresql(dot)org
> > Subject: Re: [SQL] Finding the "most recent" rows
> >
> > Try
> > SELECT the_place, max(the_time) FROM the_place GROUP BY the_place;
> >
> > Julian Scarfe wrote:
> > >
> > > I have a table (representing a set of observations) with datetime
> > fields and a
> > > non-unique place field.
> > >
> > > e.g.
> > > create table obs (
> > > the_time datetime,
> > > the_place char(8),
> > > ...other fields...
> > > )
> > >
> > > I'd like an efficient way to pull out the most recent row (i.e.
> > highest
> > > datatime) belonging to *each* of a number of places selected by a
> > simple
> > > query.
> > >
> > > e.g. given a table such as:
> > >
> > > the_time the_place ...
> > > 0910 London
> > > 1130 London
> > > 0910 Paris
> > > 0930 London
> > > 0840 Paris
> > > 1020 London
> > > 0740 Paris
> > >
> > > I'd like to select:
> > > 1130 London
> > > 0910 Paris
> > >
> > > Most of my attempts at this (as an SQL novice) feel very clumsy
> > and
> > > inefficient. Is there an efficient way of doing this in SQL?
> > > --
> > >
> > > Julian Scarfe
> >
> > --
> > Chris Bitmead
> > http://www.bigfoot.com/~chris.bitmead
> > mailto:chris(dot)bitmead(at)bigfoot(dot)com