| From: | Miguel Bernilla Sánchez <mbernilla(at)sedapal(dot)com(dot)pe> |
|---|---|
| To: | pgsql-es-ayuda(at)postgresql(dot)org |
| Subject: | Left Outer join |
| Date: | 2006-04-18 19:36:39 |
| Message-ID: | 365264531.20060418143639@sedapal.com.pe |
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| Lists: | pgsql-es-ayuda |
Sres. a continuación muestro un query y su resultado:
SELECT *
FROM weather LEFT OUTER JOIN cities ON (weather.city = cities.name);
city | temp_lo | temp_hi | prcp | date | name | location
---------------+---------+---------+------+------------+---------------+-----------
Hayward | 37 | 54 | | 1994-11-29 | |
San Francisco | 46 | 50 | 0.25 | 1994-11-27 | San Francisco | (-194,53)
San Francisco | 43 | 57 | 0 | 1994-11-29 | San Francisco | (-194,53)
(3 rows)
Simplificando... en ORACLE podría hacerlo así:
SELECT *
FROM weather.city = cities.name(+);
y en SQL SERVER (si no me equivoco):
SELECT *
FROM weather.city =* cities.name;
en POSTGRESQL existe alguna manera simplificada de hacerlo?
Gracias por sus respuestas...
--------
Saludos,
Miguel
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