From: | Ron <ronljohnsonjr(at)gmail(dot)com> |
---|---|
To: | pgsql-general(at)lists(dot)postgresql(dot)org |
Subject: | Re: Return select statement with sql case statement |
Date: | 2018-07-04 14:37:04 |
Message-ID: | 3524c35d-e566-9bad-e4bd-d493f05f2d4d@gmail.com |
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Thread: | |
Lists: | pgsql-general |
On 07/04/2018 07:48 AM, hmidi slim wrote:
> Hi,
> I need to use conditional expression in my query, So I want to make a
> query like this:
> select numberOfPremiumDays
> case when numberOfPremiumDays = date_part('day',
> ('2018-11-05'::timestamp) - ('2018-11-01'::timestamp)) then
> select product_id,
> price
> from product
> where occupation_type_id = 1
> group by product_id, occupation_type_id
>
> However, in the documentation I found that the return of case was a value,
> not like in my case I want to return a select statement.
> How can I use a conditional expression in a sql query?
> Best Regards.
The CASE clause is used to return one of many choices. Based on this
example, you need to do this:
select numberOfPremiumDays,
product_id,
price
from product
where occupation_type_id = 1
and numberOfPremiumDays = date_part('day', ('2018-11-05'::timestamp) -
('2018-11-01'::timestamp))
group by product_id, occupation_type_id
--
Angular momentum makes the world go 'round.
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