Re: Counting the number of repeated phrases in a column

On 1/27/22 10:03, Merlin Moncure wrote:
> On Wed, Jan 26, 2022 at 5:23 PM Merlin Moncure<mmoncure(at)gmail(dot)com> wrote:
>> with s as (select 'Hello World Hello World' as sentence)
>> select
>> phrase,
>> array_upper(string_to_array((select sentence from s), phrase), 1) -
>> 1 as occurrances
>> from
>> (
>> select array_to_string(x, ' ') as phrase
>> from
>> (
>> select distinct v[a:b] x
>> from regexp_split_to_array((select sentence from s), ' ') v
>> cross join lateral generate_series(1, array_upper(v, 1)) a
>> cross join lateral generate_series(a + 1, array_upper(v, 1)) b
>> ) q
>> ) q;
> Simplified to:
> select distinct array_to_string(v[a:b], ' ') phrase, count(*) as occurrences
> from regexp_split_to_array('Hello World Hello World', ' ') v
> cross join lateral generate_series(1, array_upper(v, 1)) a
> cross join lateral generate_series(a + 1, array_upper(v, 1)) b
> group by 1;
>
> phrase │ occurances
> ─────────────────────────┼────────────
> World Hello │ 1
> Hello World Hello │ 1
> Hello World │ 2
> Hello World Hello World │ 1
> World Hello World │ 1
>
> merlin
>
>
And since we're looking for repeated phrases maybe add

having count(*) > 1