Re: Can Postgres beat Oracle for regexp_count?

From: Tom Lane <tgl(at)sss(dot)pgh(dot)pa(dot)us>
To: Shaozhong SHI <shishaozhong(at)gmail(dot)com>
Cc: "David G(dot) Johnston" <david(dot)g(dot)johnston(at)gmail(dot)com>, pgsql-general <pgsql-general(at)lists(dot)postgresql(dot)org>
Subject: Re: Can Postgres beat Oracle for regexp_count?
Date: 2022-02-03 05:59:36
Message-ID: 205525.1643867976@sss.pgh.pa.us
Views: Raw Message | Whole Thread | Download mbox | Resend email
Thread:
Lists: pgsql-general

Shaozhong SHI <shishaozhong(at)gmail(dot)com> writes:
> The following has been attempted but no luck.

> select regexp_matches('My High Street', '([A-Z][a-z]+[\s]*)+', 'g')
> It is intended to match 'My High Street, but it turned out only 'Street'
> was matched.

You've got the parentheses in the wrong place, ie inside not outside the
"+" quantifier. Per the fine manual [1], the result is determined by the
last match of quantified capturing parens.

You could avoid using any capturing parens, so that the result is
the whole match:

regression=# select regexp_matches('My High Street', '(?:[A-Z][a-z]+[\s]*)+', 'g');
regexp_matches
--------------------
{"My High Street"}
(1 row)

or you could do

regression=# select regexp_matches('My High Street', '(([A-Z][a-z]+[\s]*)+)', 'g');
regexp_matches
---------------------------
{"My High Street",Street}
(1 row)

but then you have two sets of capturing parens and you get results for
both, so you might prefer

regression=# select regexp_matches('My High Street', '((?:[A-Z][a-z]+[\s]*)+)', 'g');
regexp_matches
--------------------
{"My High Street"}
(1 row)

In any case, there's no substitute for reading the manual.

regards, tom lane

[1] https://www.postgresql.org/docs/current/functions-matching.html#FUNCTIONS-POSIX-REGEXP

In response to

Responses

Browse pgsql-general by date

  From Date Subject
Next Message Michael Harris 2022-02-03 06:25:32 Re: Undetected Deadlock
Previous Message David G. Johnston 2022-02-03 05:50:35 Re: Can Postgres beat Oracle for regexp_count?