From: | Alvaro Herrera <alvherre(at)alvh(dot)no-ip(dot)org> |
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To: | "houzj(dot)fnst(at)fujitsu(dot)com" <houzj(dot)fnst(at)fujitsu(dot)com> |
Cc: | Zheng Li <zhengli10(at)gmail(dot)com>, Amit Kapila <amit(dot)kapila16(at)gmail(dot)com>, Masahiko Sawada <sawada(dot)mshk(at)gmail(dot)com>, Japin Li <japinli(at)hotmail(dot)com>, Dilip Kumar <dilipbalaut(at)gmail(dot)com>, rajesh singarapu <rajesh(dot)rs0541(at)gmail(dot)com>, PostgreSQL Hackers <pgsql-hackers(at)lists(dot)postgresql(dot)org> |
Subject: | Re: Support logical replication of DDLs |
Date: | 2022-06-23 12:43:56 |
Message-ID: | 20220623124356.gkndavscdkyg4pqq@alvherre.pgsql |
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Lists: | pgsql-general pgsql-hackers |
On 2022-Jun-15, houzj(dot)fnst(at)fujitsu(dot)com wrote:
> On Wednesday, June 15, 2022 8:14 AM Zheng Li <zhengli10(at)gmail(dot)com> wrote:
> > How does the deparser deparses CREATE FUNCTION STATEMENT? Will it
> > schema qualify
> > objects inside the function definition?
>
> The current deparser doesn't schema qualify objects inside the function
> source as we won't know the schema of inner objects until the function is
> executed. The deparser will only schema qualify the objects around
> function declaration Like:
>
> CREATE FUNCTION [public].test_func(i [pg_catalog].int4 ) RETURNS [pg_catalog].int4 LANGUAGE plpgsql
Right, this is by design. There is no way to deparse a function body --
as far as the backend is concerned, the body is just an opaque string.
That string is to be interpreted by the language handler only.
I don't know if it's possible to do different for non-core PLs, but I do
not think we have to worry about them in the Postgres implementation.
--
Álvaro Herrera PostgreSQL Developer — https://www.EnterpriseDB.com/
"La victoria es para quien se atreve a estar solo"
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