Re: pgsql: Avoid spurious deadlocks when upgrading a tuple lock

On 2019-Jun-15, Alvaro Herrera wrote:

> But that's not the danger ... with the current coding, it's initialized
> to false every time through that block; that means the tuple lock will
> never be skipped if we jump back to l3. So the danger is that the first
> iteration sets the variable, then jumps back; second iteration
> initializes the variable again, so instead of skipping the lock, it
> takes it, causing a spurious deadlock.

So, I'm too lazy today to generate a case that fully reproduces the
deadlock, because you need to stall 's2' a little bit using the
well-known advisory lock trick, but this one hits the code that would
re-initialize the variable.

I'm going to push the change of lifetime of the variable for now.

setup
{
drop table if exists tlu_job;
create table tlu_job (id integer primary key, name text);

insert into tlu_job values(1, 'a');
}

teardown
{
drop table tlu_job;
}

session "s0"
setup { begin; set deadlock_timeout=1}
step "s0_fornokeyupdate" { select id from tlu_job where id = 1 for no key update; }
step "s0_update" { update tlu_job set name = 's0' where id = 1; }
step "s0_commit" { commit; }

session "s1"
setup { begin; set deadlock_timeout=1}
step "s1_for_key_share" { select id from tlu_job where id = 1 for key share; }
step "s1_for_update" { select id from tlu_job where id = 1 for update; }
step "s1_rollback" { rollback; }

session "s2"
setup { begin; set deadlock_timeout=1}
step "s2_for_key_share" { select id from tlu_job where id = 1 for key share; }
step "s2_for_share" { select id from tlu_job where id = 1 for share; }
step "s2_rollback" { rollback; }

session "s3"
setup { begin; set deadlock_timeout=1}
step "s3_update" { update tlu_job set name = 'c' where id = 1; }
step "s3_rollback" { rollback; }

permutation "s1_for_key_share" "s2_for_key_share" "s0_fornokeyupdate" "s2_for_share" "s0_update" "s0_commit" "s1_rollback" "s2_rollback" "s3_rollback"

--
Álvaro Herrera https://www.2ndQuadrant.com/
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