From: | Gary Stainburn <gary(dot)stainburn(at)ringways(dot)co(dot)uk> |
---|---|
To: | "pgsql-sql(at)lists(dot)postgresql(dot)org" <pgsql-sql(at)lists(dot)postgresql(dot)org> |
Subject: | left outer join to pull in most recent record |
Date: | 2018-10-09 13:18:01 |
Message-ID: | 201810091418.01620.gary.stainburn@ringways.co.uk |
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Lists: | pgsql-sql |
I have the following stock list table.
# select * from stock;
s_stock_no | s_regno
------------+---------
N12345 | GPS1
N12346 | TEST1
U123 | GPS1
(3 rows)
This shows two vehicles.
GPS1 was originally a new vehicle which we then sold.
TEST1 is also a new vehicle
GPS1 is sunsequently purchased back from the customer as a part exchange, and
is put on the stock table as a used car.
If I later want to do a search based on the registration number, wishing to
retrieve the most recent record what is the *best* (quickest or least CPU
time depending on your preference) way to do this?
By most recent record, I mean the record with the highest stock number.
I'm looking for a solution to do a straight select where.....
but I am also looking for a solution that can be used in a left join, for
example
select diary.*, stock.*
from diary
left outer join stock on ...........
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