From: | Andres Freund <andres(at)2ndquadrant(dot)com> |
---|---|
To: | Noah Misch <noah(at)leadboat(dot)com> |
Cc: | Robert Haas <robertmhaas(at)gmail(dot)com>, David Rowley <dgrowleyml(at)gmail(dot)com>, PostgreSQL-development <pgsql-hackers(at)postgresql(dot)org> |
Subject: | Re: signed vs. unsigned in TYPEALIGN (was Re: space reserved for WAL record does not match what was written: panic on windows) |
Date: | 2013-10-17 22:10:17 |
Message-ID: | 20131017221017.GC442708@alap2.anarazel.de |
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On 2013-10-17 18:04:34 -0400, Noah Misch wrote:
> On Thu, Oct 17, 2013 at 08:27:01PM +0200, Andres Freund wrote:
> > On 2013-10-17 12:33:45 -0400, Noah Misch wrote:
> > > > 1. Is there any guarantee that sizeof(intptr_t) >= sizeof(size_t)?
> > > > (Note that Size is just a typedef for size_t, in c.h)
> > >
> > > C99 doesn't require it, but I have never heard of a platform where it is
> > > false. sizeof(intptr_t) > sizeof(size_t) systems have existed.
> >
> > Either way, both have to be at least 4byte on 32bit platforms and 8byte
> > on 64bit ones. So I as well think we're good.
>
> C99 does not have concepts like "32bit platform" and "64bit platform", so it
> cannot make such a constraint. Nonetheless, I agree we're good with respect
> to implementations actually worth anticipating.
But afaik we indirectly require either 4 or 8 byte pointers or in
configure. And we have a requirement for non-segmented memory afaics. So
both size_t and intptr_t have to be big enough to store a pointer. Which
in turn implies that they have to be at least 4/8 bytes.
> Having said that, changing the ancient macros to use uintptr_t does have the
> advantage you mention, and I'm failing to think of a disadvantage.
+1
Greetings,
Andres Freund
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