| From: | "ktm(at)rice(dot)edu" <ktm(at)rice(dot)edu> |
|---|---|
| To: | James Sharrett <jsharrett(at)tidemark(dot)net> |
| Cc: | pgsql-sql(at)postgresql(dot)org |
| Subject: | Re: how can I replace all instances of a pattern |
| Date: | 2013-03-26 13:18:52 |
| Message-ID: | 20130326131852.GF32580@aart.rice.edu |
| Views: | Raw Message | Whole Thread | Download mbox | Resend email |
| Thread: | |
| Lists: | pgsql-sql |
On Tue, Mar 26, 2013 at 09:13:39AM -0400, James Sharrett wrote:
> Sorry, caught a typo. Mytext1 is correctly replaced because only one
> instance of the character (space) is in the string.
>
> This deals with the correct characters but only does the first instance of
> the character so the output is:
>
> 'Mytext1'
> 'Mytext 2' (wrong)
> 'Mytext-3' (wrong)
> 'My_text4'
> 'My!text5'
>
Hi James,
Try adding the g flag to the regex (for global). From the documentation:
regexp_replace('foobarbaz', 'b..', 'X')
fooXbaz
regexp_replace('foobarbaz', 'b..', 'X', 'g')
fooXX
regexp_replace('foobarbaz', 'b(..)', E'X\\1Y', 'g')
fooXarYXazY
Regards,
Ken
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