GROUP and ORDER BY

Hello,

I would like to GROUP the result by one column and ORDER it by another:

SELECT
no, name, similarity(name, 'Tooneyvara') AS s
FROM vtown
WHERE similarity(name, 'Tooneyvara') > 0.4
ORDER BY s DESC

Result:

1787 "Toomyvara" 0.5
1787 "Toomevara" 0.4
1188 "Toonybara" 0.4

Desired result:

1787 "Toomyvara" 0.5
1188 "Toonybara" 0.4

Gets rid of the duplicate "no" keeping the spelling with the greater
similarity and presents the remaining result ordered by similarity.

My solution:

SELECT * FROM
(
SELECT DISTINCT ON (no)
no, name,
similarity(name, 'Tooneyvara') AS sim
FROM vtown
WHERE similarity(name, 'Tooneyvara') > 0.4
ORDER BY no, sim DESC
) AS x
ORDER BY sim

Is that the best way to achieve this result?
--

Best Regards,
Tarlika Elisabeth Schmitz