From: | David W Noon <dwnoon(at)ntlworld(dot)com> |
---|---|
To: | pgsql-sql(at)postgresql(dot)org |
Subject: | Re: foreign keys and lots of tables |
Date: | 2011-05-19 00:09:07 |
Message-ID: | 20110519010907.770c8c48@karnak.local |
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Thread: | |
Lists: | pgsql-sql |
On Wed, 18 May 2011 20:10:19 +0100, Gary Stainburn wrote about [SQL]
foreign keys and lots of tables:
>I have the following tables (individual seat allocation removed to
>make it simpler)
Omitting details makes the problem more difficult to comprehend.
[snip]
>create table booking_seats (
> b_id int4 not null references bookings(b_id),
> c_id int4, -- carriage ID
> c_seat varchar(10) -- seat label
>);
>
>The following ensures the seat exists on the coach. (not shown)
>
>alter table booking_seats add constraint seat_exists
> foreign key (c_id, c_seat) references coach_seats (c_id,c_seat);
>
>How would I ensure that the coach exists on the train. I would need to
>convert the b_id to a t_id using the bookings table and I don't know
>how.
I think you will need to write a trigger procedure with something like
the following query inside it:
IF NOT EXISTS(SELECT * FROM train_coaches AS tc
INNER JOIN bookings AS b ON b.t_id = tc.t_id
WHERE b.b_id = NEW.b_id AND tc.c_id = NEW.c_id)) THEN
-- Something is wrong.
You cannot use a subquery in a CHECK constraint, so I think a trigger
will be the go.
>To complicate things, when the initial booking is made, bot c_id and
>c_seat are NULL. Will this make any difference?
If c_id is NULL you cannot check anything against it, so your data
integrity has just gone for a Burton.
--
Regards,
Dave [RLU #314465]
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dwnoon(at)ntlworld(dot)com (David W Noon)
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