find the greatest, pick it up and group by

I've a table like:

CREATE TABLE ordiniitem
(
idordine numeric(18,0) NOT NULL,
grupposped smallint,
idart numeric(18,0) NOT NULL,
qevasa integer,
qfuoricat integer,
qinris integer,
qnonpub integer,
qann integer,
qord integer,
qpren integer,
qrichpag integer,
qinriass integer,
qinesa integer
);

I'd like to group by idordine, grupposped, idart.
For every row grouped that way, I'd like to pick the greatest of the
q* columns and insert:
idordine, grupposped, idart, name of the greatest(q*) in a new table.
I don't mind if more than one q* column is equal to greatest(q*). It
should pick up one, just one no matter which among the one equal to
greatest(q*).

I think this way works but it hurts my eyes. Any alternative
approach?

SELECT
ioi.idordine,
ioi.grupposped,
ioi.idart,
-- ioi.quantita,
case
when ioi.qevasa =
greatest(
ioi.qevasa, ioi.qfuoricat,
ioi.qinris, ioi.qnonpub, ioi.qann, ioi.qord, ioi.qpren,
ioi.qrichpag, ioi.qinriass, ioi.qinesa )
then 'evaso'
when ioi.qfuoricat =
greatest(
ioi.qevasa, ioi.qfuoricat,
ioi.qinris, ioi.qnonpub, ioi.qann, ioi.qord, ioi.qpren,
ioi.qrichpag, ioi.qinriass, ioi.qinesa )
then 'fuoricatalogo'
when ioi.qinris =
greatest(
ioi.qevasa, ioi.qfuoricat,
ioi.qinris, ioi.qnonpub, ioi.qann, ioi.qord, ioi.qpren,
ioi.qrichpag, ioi.qinriass, ioi.qinesa )
then 'in ristampa'

-- ...

end
FROM
ordiniitem ioi
group by
ioi.idordine,
ioi.grupposped,
ioi.idart,
ioi.qevasa, ioi.qfuoricat, ioi.qinris,
ioi.qnonpub, ioi.qann, ioi.qord, ioi.qpren,
ioi.qrichpag, ioi.qinriass, ioi.qinesa
;

thanks

--
Ivan Sergio Borgonovo
http://www.webthatworks.it