From: | Leif Biberg Kristensen <leif(at)solumslekt(dot)org> |
---|---|
To: | pgsql-sql(at)postgresql(dot)org |
Subject: | Re: replace " with nothing |
Date: | 2011-05-11 21:11:07 |
Message-ID: | 201105112311.08016.leif@solumslekt.org |
Views: | Raw Message | Whole Thread | Download mbox | Resend email |
Thread: | |
Lists: | pgsql-sql |
On Wednesday 11 May 2011 22:29:40 Tony Capobianco wrote:
> We are converting from Oracle to Postgres. An Oracle script contains
> this line:
>
> select replace(firstname,'"'), memberid, emailaddress from members;
>
> in an effort to replace the " with nothing. How can I achieve the same
> result with Postgres?
>
> Here's the Postgres error I get:
>
> select replace(firstname,'"'), memberid, emailaddress from members;
> ERROR: function replace(character varying, unknown) does not exist
> LINE 1: select replace(firstname,'"'), memberid, emailaddress from m...
From the fine documentation
<http://www.postgresql.org/docs/current/static/functions-string.html>
replace(string text, from text, to text)
Example: replace('abcdefabcdef', 'cd', 'XX')
IOW, this function takes three parameters, the first one being the actual text
you want to make a replace on. Yor ecample above shoul probably be written as:
SELECT REPLACE((SELECT firstname FROM members), '%', ''), memberid,
emailaddress FROM members;
although it's a little above me why you would want to select firstname in the
first place when you proceed to replace it with nothing.
regards, Leif
From | Date | Subject | |
---|---|---|---|
Next Message | Ross J. Reedstrom | 2011-05-11 21:22:32 | Re: replace " with nothing |
Previous Message | Lew | 2011-05-11 20:53:42 | Re: replace " with nothing |