| From: | Leif Biberg Kristensen <leif(at)solumslekt(dot)org> | 
|---|---|
| To: | pgsql-sql(at)postgresql(dot)org | 
| Subject: | Re: replace " with nothing | 
| Date: | 2011-05-11 21:11:07 | 
| Message-ID: | 201105112311.08016.leif@solumslekt.org | 
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| Lists: | pgsql-sql | 
On Wednesday 11 May 2011 22:29:40 Tony Capobianco wrote:
> We are converting from Oracle to Postgres.  An Oracle script contains
> this line:
> 
>  select replace(firstname,'"'), memberid, emailaddress from members;
> 
> in an effort to replace the " with nothing.  How can I achieve the same
> result with Postgres?
> 
> Here's the Postgres error I get:
> 
> select replace(firstname,'"'), memberid, emailaddress from members;
> ERROR:  function replace(character varying, unknown) does not exist
> LINE 1: select replace(firstname,'"'), memberid, emailaddress from m...
From the fine documentation 
<http://www.postgresql.org/docs/current/static/functions-string.html>
replace(string text, from text, to text)
Example: replace('abcdefabcdef', 'cd', 'XX')
IOW, this function takes three parameters, the first one being the actual text 
you want to make a replace on. Yor ecample above shoul probably be written as:
SELECT REPLACE((SELECT firstname FROM members), '%', ''), memberid, 
emailaddress FROM members;
although it's a little above me why you would want to select firstname in the 
first place when you proceed to replace it with nothing.
regards, Leif
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