Re: LIKE problem

In response to Juan Pablo Cook :
> Hi Everybody! 
> I'm asking you, because recently I have some problems with the LIKE so I test
> with an easy and simple query but doesn't work:
>
> SELECT *
> FROM employee
> WHERE id like 'h%';
>
> The error says:
> "ERROR:  operator does not exist: integer ~~ unknown
>
> LINE 5: WHERE id like 'h%';
>
>                   ^
>
> HINT:  No operator matches the given name and argument type(s). You might need
> to add explicit type casts.

You can't compare a INT with a TEXT:

test=*# select '1'::int4 like '1'::text;
ERROR: operator does not exist: integer ~~ text
LINE 1: select '1'::int4 like '1'::text;
^
HINT: No operator matches the given name and argument type(s). You
might need to add explicit type casts.

But you can CAST the INT into a TEXT:

test=# select '1'::int4::text like '1%'::text;
?column?
----------
t
(1 row)

Okay?

But in your case,you have an INT-column (id) and you compare that with
'h%'. You can CAST the id-column, but all INT::TEXT don't match 'h%'.

--
Andreas Kretschmer
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