Re: hi

On Tue, 24 Apr 2007, Penchalaiah P. wrote:

> Hi
>
> I have the data like this in temp table
>
> SQL> Select sno, value from temp;
>
> SNO Value
>
> 1 650.00
>
> 2 850.00
>
> 3 640.00
>
> 3 985.00
>
> 5 987.00
>
> 9 9864.00
>
> 7 875.00

Tables are not ordered. You'll need something like an ordering column
that represents the ordering and is unique.

Then you can probably do something like (untested):
select sno, value, (select sum(value) as sum from temp t where t.ordering
<= temp.ordering) from temp order by ordering;
or
select t1.sno, t1.value, sum(t2.value) from temp as t1, temp as t2 where
t1.ordering >= t2.ordering group by t1.ordering, t1.sno, t1.value order
by t1.ordering;